1.

Two first order reactions have half lives in the ratio 3:2. If t_(1) and t_(2) are the time periods for 25% and 75% completion for the first and second reactions respectiely find t_(1):t_(2)

Answer»

`0.311:1`
`0.420:1`
`0.273:1`
`0.119:1`

Solution :1st:100% `OVERSET(t_(1//2)=3)(to)50%overset(t_(1//2)=3)(to)25%2ND, 100%overset(t_(1//2)=2)(to)50%overset(t_(1//2)=2)(to)25%`
`impliesK_(1)xxt_(25)=2.303log(100/75)impliesK_(2)xxt_(75)=2.3031log(100/25)`
`((0.693/3))/((0.693/2))XX(t_(1))/(t_(2))=("log"4/3)/(log4),2/3xx(t_(1))/(t_(2)),2/3xx(t_(1))/(t_(2))=(log4-LOG3)/(log4),(t_(1))/(t_(2))=3/2xx((log4)/(log4)-(log3)/(log4))`
`=3/2xx(1-0.4771/0.6020)=3/2xx(1-0.7925)=3/2xx0.207475=0.311`


Discussion

No Comment Found

Related InterviewSolutions