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Two fixed frictionless inclined plane making angles `30^(@)` and `60^(@)` with the vertical are shown in the figure. Two blocks A and B are placed on the two planes What is the relative vertical acceleration of A with respect to B ? |
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Answer» `mg sin theta = ma rArr a = g sin theta` where a is along the inclined plane `:.` vertical component of acceleration is `g sin^(2) theta` `a_(r) =a_(AB) =a_(A) -a_(B)` `:.` relative vertical acceleration of `A` with respect to `B` is `g (sin^(2) 60^(0) - sin^(2) 30^(0)) = (g)/(2) =4.9ms^(-2)` (in vertical direction) . |
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