1.

Two flask X and Y have volume 1 L and 2 L respectively and each of them contain 1mole of same ideal gas. The temperature of the flask are so adjusted that average speed of molecules in X is twice as those in Y. The pressure in flask X would be:

Answer»

<P>same as that in Y
half of that in Y
`(1)/(8)TH` of that in Y
8 times of that in Y

Solution :`PV=(1)/(3)MnU_("rms")^(2)`
SINCE `(U_(avg))_(x)=2(U_(avg))_(y)`
`P_(x)(I)=4xxP_(y)xx2`
`P_(x)=8P_(y)`


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