Two flasks R and S of volume V_(1)andV_(2) contain same gas at pressure P_(1)andP_(2) respectively at the same temperature. Pressure of the gas when the flasks R and S are connected by a tube of negligible volume is

Two flasks R and S of volume V_(1)andV_(2) contain same gas at pressur

1.	Two flasks R and S of volume V_(1)andV_(2) contain same gas at pressure P_(1)andP_(2) respectively at the same temperature. Pressure of the gas when the flasks R and S are connected by a tube of negligible volume is
Answer» <P>`(P_(1)V_(1)+P_(2)V_(2))/(V_(1)+V_(2))` `(P_(1)V_(1)+P_(2)V_(2))/(2(V_(1)+V_(2)))` `(P_(1)V_(2)+P_(2)V_(1))/(V_(1)+V_(2))` `((P_(1)+P_(2))(V_(1)+V_(2)))/((V_(1)+2V_(2)))` Solution :Number of MOLES of GAS in two flasks are `n_(1)=(P_(1)V_(1))/(RT)andn_(2)=(P_(2)V_(2))/(RT)because N=n_(1)+n_(2)` `therefore P=((n_(1)+n_(2))RT)/(V_(1)+V_(2))=(P_(1)V_(1)+P_(2)V_(2))/(V_(1)+V_(2))`