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Two force are equal and opposite in direction exerted on a bar (rod) as shown in figure. Hence plane PQ makes an angle theta with the cross-section 'a'. Find the tensile stress on PQ. |
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Answer» Solution :In `DELTA PRQ, (PR)/(PQ) = COS THETA, ` Area of PR =a `therefore (a)/(PQ) = cos theta` `therefore` Tensile STRESS `= (F.)/(PQ)=(F cos theta)/(a //cos theta) = (F cos ^(2) theta )/(a)` |
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