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Two forces with magnitudes of 20pounds and 14 pounds and an angle of55° between them are applied to anobject. Find the magnitude of theresultant vector to the nearest wholenumber? pls, solve this for me:( |
Answer» Answer: Here's one way to simply find the MAGNITUDE of the resultant force- finding the angle of the resultant involves additional STEPS. If you need that as well, draw a parallelogram and use the Law of Cosines. If you imagine a box being pulled buy the forces and assume 14# VECTOR is pulling horizontally, the component form for it would be: 14i + 0j From the same location that the14# force is pulling from, the 20# vector is also pulling but at a 55 degree angle higher. In component form, the 20# vector would be: 20 COS 55 i + 20 sin 55 j Using vector addition, the resultant vector would be: (14 + 20cos55) i + (0 + 20SIN 55) j = 24.47 i + 16.38 j The magnitude of the resultant vector: r= sqrt( 24.47^2 + 16.38^2) = 29 pounds |
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