1.

Two functions `f:R to R and g:Rto R` are defined as follows: `f(x)={{:(,0,x in Q),(,1,x ne Q):},g(x)={{:(,-1,x in Q),(,0,x in Q):}` Then, fof (e)+fog`(pi)`A. `-1`B. 0C. 1D. 2

Answer» Correct Answer - A
We have
`gof(e)+fog(pi)=g(f(e))+f(g(pi)) =g(1)+f(0)=-1+0=-1`


Discussion

No Comment Found