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Two functions `f:R to R and g:Rto R` are defined as follows: `f(x)={{:(,0,x in Q),(,1,x ne Q):},g(x)={{:(,-1,x in Q),(,0,x in Q):}` Then, fof (e)+fog`(pi)`A. `-1`B. 0C. 1D. 2 |
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Answer» Correct Answer - A We have `gof(e)+fog(pi)=g(f(e))+f(g(pi)) =g(1)+f(0)=-1+0=-1` |
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