Two gas bulbs A and B are connected by a tube having a stopcock. Bulb A has a valume of 100 mL and contains hydrogen. After opening the gas from A to the evacuated bulb B, the pressure falls down by 40%. The volume (mL) of B must be

Two gas bulbs A and B are connected by a tube having a stopcock. Bulb

1.	Two gas bulbs A and B are connected by a tube having a stopcock. Bulb A has a valume of 100 mL and contains hydrogen. After opening the gas from A to the evacuated bulb B, the pressure falls down by 40%. The volume (mL) of B must be
Answer» 75 150 125 200 Solution :APPLYING BOYLE's LAW `P_(A)V_(A)=(0.40P_(A))(V_(A)+V_(B))` `P_(A)xx100=0.40P_(A)(100+V_(B))` or `100=0.4(100+V_(B))` or `100+V_(B)=250` or `V_(B)=150 mL`.