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Two gases A and B are filled in a container. The experimental rate law for the reaction between them, has been found to be Rate =k [A]^2[B]Predict the effect on the rate of the reaction when pressure is doubled : |
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Answer» the RATE is doubled `Rate_1=k(P_A)^2(P_B)` `Rate_2=k(2P_A)(2P_B)` `:. (Rate_2)/(Rate_2)= (k(2P_A)^2(2P_B))/(k(P_A)^2(P_B))` `=(2)^2xx 2= 8` |
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