1.

Two gases A and B having molecular weights 60 and 45 respectively are enclosed in a vessel. The weight of A is 0.5 g and that of B is 0.2 g. The total pressure of the mixture is 750 mm. Calculate the partial pressure of the two gases.

Answer»

SOLUTION :Mole of `A = (0.50)/(60) = 0.0083`
Mole of B `= (0.20)/(45) = 0.0044`
Total mole = 0.0127
Total PRESSURE = 750 mm.
Partial pressure of `A = ("MOLES of A")/("total moles") XX "total pressure"`
`= (0.0083)/(0.0127) xx 750 = 490 mm`.
Partial pressure of B `= ("0.0044)/(0.0127) xx 750 = 260 mm`


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