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Two gases A and B having molecular weigths 60 and 45 respectively are enclosed in a vessel. The wt. of A is 0.50 g and that of B is 0.2 g. The total pressure of mixture is 750 mm. Calculate partial pressure of the two gases. |
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Answer» SOLUTION :Given wt. of gas A=0.50 g mol wt. of gas A=60 Wt, of gas B =0.2 g. Molecular wt. gas B =45 `P_(T) =750 mm` From Dalton.s law of PARTIAL pressure `P_(A) =P_(T) xx` MOLE frection of A. `=750 xx (0.50//60)/((0.50)/(60)+(0.2)/(45))=489.23 mm`. `P_(T) =P_(A) +P_(B)` `THEREFORE P_(B) =P_(T)-P_(A)=750-489.23` `=260.77 mm`. |
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