Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively, the molecular mass of 'A' is 49 amu. Molecular mass of 'b' will be:

Two gases A and B having the same volume diffuse through a porous part

1.	Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively, the molecular mass of 'A' is 49 amu. Molecular mass of 'b' will be:
Answer» 25 amu 50 amu 12.25 amu 6.50 amu Solution :`(r_(1))/(r_(2)) = SQRT((m_(2))/(m_(1)))` `(V//20)/(V//10) = sqrt((m_(2))/(49))` `(1)/(2) = sqrt((m_(2))/(49))` `m_(2) = 12.25 am u`