1.

Two gases A and B having the same volume, diffuse through a porous partition in 20 and 10seconds respectively. The molecular mass of A is 49 u.Molecular mass ofB will be

Answer»

50.00 u
12.25 u
6.50 u
25.00 u

Solution :We knowthat , ` r_(A)/(r_(B)) = (V//t_(A))/(V//t_(B)) = sqrt((M_(B)/(M_(A)))`
` t_(B)/t_(A) =sqrt(M_(B)/M_(A)) Rightarrow10/20 = sqrt(M_(B)/49) Rightarrow(10/20)^(2) = M_(B)/49`
` 100/400= M_(B)/49 Rightarrow= M_(B) = ( 49 XX 100)/400 =12.25 u`


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