1.

Two gases N_(2)and H_(2) are allowed to react from mixture of N_(2)H_(2)(1) and N_(2)H_(4)(g) leaving none of the reactants. Formation of N_(2)H_(2) (1) does not create any energy change whereas formation of 1 ml N_(2)H_(4)(g) absorbs 2 Joule energy. Ratio of volume contraction to energy change (in ml/Joule) during reaction when 30 ml N_(2)and 40 ml H_(2) react under similar conditions of temperature and pressure.

Answer»

Solution :`N_(2)+H_(2)toN_(2)H_(2)(1)+N_(2)H_(4)(g)`
`POAC on H ""a ML""bml`
`30xx2=2a+2bimpliesa+b=30`
`POAC on H40xx2=2a+4bimpliesa+2b=30`
`b=10,a=20`
`V.C.=(30+40)-10=60ml`
Energy change `=10xx2=20`
`(V.C.)/("Energy change")=(60)/(20)=3`


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