Two grams of a mixture of propane and actylene is burnt in excess oxygen. The unreacted oxygen is removed by adsorption into basic pyrogallol. The ratio of volumes of gaseous CO_(2) and H_(2)O is 3:2. Determine the mass of unsaturated hydrocarbon in the given mixture.

Two grams of a mixture of propane and actylene is burnt in excess oxyg

1.	Two grams of a mixture of propane and actylene is burnt in excess oxygen. The unreacted oxygen is removed by adsorption into basic pyrogallol. The ratio of volumes of gaseous CO_(2) and H_(2)O is 3:2. Determine the mass of unsaturated hydrocarbon in the given mixture.
Answer» Solution :The stoichimetric equations for the conbustion of hydrocarbons are `C_(8)H_(8)overset(O_(2))to3CO_(2)+4H_(2)O,C_(2)H_(2) overset(O_(2))to2CO_(2)+H_(2)O` LET the number of moles of `C_(2)H_(2)` is x Let the number of moles of `C_(3)H_(8)` is y Ratio of VOLUMES is equal to ratio of moles `(" number of moles of "CO_(2))/("number of moles of "H_(2)O )=(3)/(2)=(2x+3y)/(x+4y)` SOLVING, x:y =6:1 The ratio of weights of `C_(2)H_(2)` and `C_(3)H_(8)` = `6xx26:1xx44=156:44` MASS of `C_(2)H_(2)` in the given mixture `=(156)/(156+44)xx2=1.56` grams