Two grams of pure caustic soda is present dissolved in 1.5 Lit solution. If 10mL of this is diluted to 150mL. What is the normality of diluted base?

Two grams of pure caustic soda is present dissolved in 1.5 Lit solutio

1.	Two grams of pure caustic soda is present dissolved in 1.5 Lit solution. If 10mL of this is diluted to 150mL. What is the normality of diluted base?
Answer» Solution :Number of MOLES of caustic soda `("WEIGHT")/(GMW)=(2)/(40)=0.05` Normality `=(0.05)/(1.5)=0.0333eq L^(-1)` Equation for DILUTION `=V_(1)N_(1) -V_(2)N_(2)` Normality of dilute solution `=N_(2)=(V_(1)N_(1))/(V_(2))=(10xx0.0333)/(150)=0.00222eq L^(-1)`