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Two grams sulphur is completely burnt in oxygen to form `SO_(2)`. In this reaction, what is the volume (in litres) of oxygen consumed at S.T.P. ?(at mass of S and O are 32 and 16 respectively)A. `(16)/(22.414)`B. `(22.414)/(16)`C. `(22.414)/(32)`D. `(32)/(22.414)` |
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Answer» Correct Answer - B `underset(32g)(S)+underset(22.414L)(O_(2))toSO_(2)` 32 g S required `O_(2)` at S.T.P. = 22414 L 2 g of S require `O_(2)` at S.T.P. `= (22.414)/(32)xxL` `=(22.414)/(16)L` |
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