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Two graphs of the same projectile motion (in the x - y plane) projected from origin are shown in (Fig. 5 .10). X - axis is along horozontal direction and Y - axis is vertically upwards. Take `g = 10 m s^2` Find (i) The y component of initial velocity and (ii) the `X` component of initial velocity. . |
Answer» From garph (i) : `v_y = 0 at t = (1)/(2) s`, i.,e., time taken to reach maximum height `H` is `t = (u_y)/(g) = (1)/(2) rArr u_y = 5 m s^-1` From graph (2) , `v_y = 0 at x = 2 m`, i.,e., when the particle is at maximum height, its displacement along horizontal, `x = 2 m`. `x = u_x xx t rArr 2 = u_x xx (1)/(2) rArr u_ x = 4 m s^-1`. |
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