1.

Two half cell reactions are given as : (i) Fe_(aq)^(2+)+2e^(-) to Fe_((s)),E^(@)=-0.44" V " (ii) 2H_((aq))^(+)+(1)/(2)O_(2)(g)+2e^(-) to H_(2)O(l),E^(@)=+1.23" V " The E^(@) for the reaction Fe_(s)+2H^(+)+(1)/(2)O_(2)(g) to Fe_(aq)^(2+)+H_(2)O_(l) is

Answer»

`+1.67" V "`
`-1.67" V "`
`+0.79" V "`
`-0.79" V "`

Solution :(a) Subtract EQUATION (i) from equation (ii) to GET equation (III) `E^(@)=(+1.23)-(-0.44)=+1.67" V "`.


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