Two heaters are marked 200V, 300W and 200 V, 600 W. If the heaters are combined in series and the combination connected to a 200 V dc supply, which heater will produce more heat ?

Two heaters are marked 200V, 300W and 200 V, 600 W. If the heaters are

1.	Two heaters are marked 200V, 300W and 200 V, 600 W. If the heaters are combined in series and the combination connected to a 200 V dc supply, which heater will produce more heat ?
Answer» Resistance of the two heaters are `R_(1) = V^(2)/P_(1) = (200 xx 200)/300 = 400/3 Omega` `R_(2) = V^(2)/P_(2) = (200 xx 200)/600 = 200/3 Omega` For series combination, the effective resistance is `R = R_(1) + R_(2) = 400/3 + 200/3 = 600/3 = 200 Omega` Current, `I = V/R = 200/200 = 1A` Power dissipated in 1st heater, `P_(1) = I^(2) R_(1) = 1^(2) xx 400/3 = 400/3 W` Power dissipated in second heater, `P_(2) = I^(2)R_(2) = 1^(2) xx 200/3 = 200/3 W` `:. P_(1) = 2 P_(2) or P_(1) gt P_(2)`

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Two heaters are marked 200V, 300W and 200 V, 600 W. If the heaters are combined in series and the combination connected to a 200 V dc supply, which heater will produce more heat ?

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