Two ideal gas thermometers A and B use oxyge,i and hydrogen respectively. The following observations are made.(##AKS_NEO_CAO_PHY_XI_V01_PMH_C12_SLV_011_Q01.png" width="80%"> (a) Whal is the absolute temperature of normal melti.ng point of sulphur as read by thermometer A and B ? (b) What do you think is the reason/or slightly different answers from A and B ?

Two ideal gas thermometers A and B use oxyge,i and hydrogen respective

1.	Two ideal gas thermometers A and B use oxyge,i and hydrogen respectively. The following observations are made.(##AKS_NEO_CAO_PHY_XI_V01_PMH_C12_SLV_011_Q01.png" width="80%"> (a) Whal is the absolute temperature of normal melti.ng point of sulphur as read by thermometer A and B ? (b) What do you think is the reason/or slightly different answers from A and B ?
Answer» Solution :(a) For THERMOMETER A, `T_(tr) 273 K "" P_(tr) 1.250 x 10^(5)` Pa and T = ? , P = `1.797 xx 10^(5)` Pa We have T = `(P)/(P_(tr)) xx T_(tr) = (1.797xx 10^(5))/(1.250 xx 10^(5)) xx 273 = 392.46` K For thermometer B `T_(tr) = 273K , P_(tr) = 0.2 xx 10^(5) `Pa T = ? , P = 0.287 `xx 10^(5) " pa "T = (P)/(P_(tr)) xx T_(tr) = (0.287 xx 10^(5) xx 273 )/(0.2 xx 10^(5) = 391.75 `K The slight difference in temperature as read by two thermometers A and B are due to the FACT that oxygen and HYDROGEN do not behave like IDEAL gas.