Two identical blocks A and B each of mass M are connected to each other through a ligh string. The system is placed on a smooth horizontal floor. When a constant force F is applied horizontally on the block A, find the tension in the string.

Two identical blocks A and B each of mass M are connected to each othe

1.	Two identical blocks A and B each of mass M are connected to each other through a ligh string. The system is placed on a smooth horizontal floor. When a constant force F is applied horizontally on the block A, find the tension in the string.
Answer» SOLUTION :The acceleration of the system of two blocks A and `B=("Force")/("Total mass")` `therefore a=(F)/(M+M)=(F)/(2M)` If we CONSIDER the free body diagram of A, the forces ACTING on it are (i) the applied force F and (ii) the tension T on the string as shown in the following fig. The RESULTANT force `= F-T , Ma = F-T` `M((F)/(2M))=F-T "" (therefore a=(F)/(2M))` `(F)/(2)=F-T` `T=(F)/(2)` (or) From FBD for B `T=Ma=M(F)/(2M)=(F)/(2)` `T=(F)/(2)`