Two identical cells each of emf `epsilon`, having negligible internal reistance r, are connercted in parallel with each other across an external resistance R. What is the current through this resistance.

Two identical cells each of emf `epsilon`, having negligible internal

1.	Two identical cells each of emf `epsilon`, having negligible internal reistance r, are connercted in parallel with each other across an external resistance R. What is the current through this resistance.
Answer» The cells are arranged as shown in the circuit diagram. As the internal resistance is negligible, so total resistance of the circuit = R. So, current through the resistance, `I = (E)/(R)`.

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Two identical cells each of emf `epsilon`, having negligible internal reistance r, are connercted in parallel with each other across an external resistance R. What is the current through this resistance.

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