Two identical concentric rings each of mass (m) and radius (r ) placed perpendicularly. So the moment of inertia about axis of one of the ring is …………..

Two identical concentric rings each of mass (m) and radius (r ) placed

1.	Two identical concentric rings each of mass (m) and radius (r ) placed perpendicularly. So the moment of inertia about axis of one of the ring is …………..
Answer» `(1)/(2)mr^(2)` `mr^(2)` `(3)/(2)mr^(2)` `2mr^(2)` Solution : `I_(1)` = Moment of inertia about diameter = `(1)/(2)mr^(2)` `I_(2)` = Moment of inertia about AXIS PASSING through centre and PERPENDICULAR to plane = `mr^(2)` `I=I_(1)+I_(2)=(1)/(2)mr^(2)+mr^(2)=(3)/(2)mr^(2)`