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Two identical conducting spheres A and B, carry equal charge. They are separated by a distance much larger than their diameters, and the force between them is F. A third identical conducting spheres, C,is uncharged. Sphere C is first touched to A, then to B, and then removed. As a result, the force between A and B would be equal to :A. FB. `(3F)/(8)`C. `(3F)/(4)`D. `(F)/(2)` |
Answer» Correct Answer - B | |