InterviewSolution
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InterviewSolution
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Two identical containers A and B are filled with two different liquids of equal masses. The level of the liquid in container A is found to be one-fourth of the level of the liquid in container B. What is the ratio of thedensity of two liquids? If the density of he liquid in the container A is 2 " g "` cm^(-3)`, then find the density of the mixture of the two liquids. |
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Answer» Mass of liquid A, `(m_(A))` = mass of liquid B, `(m_(B))` Volume = `area xx height` Area of cross section of A = Area cross section of B Height of liquid column A = `1/4 xx` " height " of liquid column A = `1/4 " (Volume of B) " Density of `"mass/volume"` `(density " of " A)/(density " of " B) = m_(A)/V_(A)xx V_(B)/m_(B)=V_(B)/V_(B)=4/1=4 :1` If density of A is 2 " g " `cm^(-3)` ,then density of B = " g " `cm^(-3)` = 0.5 " g " `cm^(-3)` Density of mixture = `"mass of mixture"/"volume of mixture"` `(m_(A)+m_(B))/(v_(A)+v_(B))=(m_(A)=m_(A))/(v_(A)=4v_(A)) ( :. m_(B) = m_(A) and v_(B)= 4v_(A))` `(2m_(A))/(5v_(A)) = (2xx d_(A)xx v_(A))/(5V_(A)` `(2xx2)/5=4/5=0.8 " g "cm^(-3)` |
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