InterviewSolution
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InterviewSolution
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Two identical containers A and B with frictionless pistons contain the same ideal gas at the same temperature and the same velocity V. The mass of the gas in A is `m_A,` and that in B is `m_B`. The gas in each cylinder is now allowed to expand isothermally to the same final volume 2V. The changes in the pressure in A and B are found to be `DeltaP and 1.5 DeltaP` respectively. ThenA. `4m_(A)=9m_(B)`B. `2m_(A)=3m_(B)`C. `3m_(A)=2m_(B)`D. `9m_(A)=3m_(B)` |
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Answer» Correct Answer - C Process is isothermal , therefore `T`= constant `(P prop 1/V)` volume is increasing , therefore pressure will decreases. In chamber A: `Delta P = P_(i)-P_(f)=(mu_(A)RT)/(V)-(mu_(A)RT)/(2V)=(mu_(A)RT)/(2V)`...(i) In chamber B: `1.5DeltaP=P_(i)-P_(f)=(mu_(B)RT)/(V)-(mu_(B)RT)/(2V)=(mu_(B)RT)/(2V)`....(ii) From equation (i) and (ii) `(mu_A)/(mu_B) = 1/1.5 = 2/3` `implies (m_(A)//M)/(m_(B)//M) = 2/3implies 3m_(A) = 2m_(B)`. |
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