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Two identical containers joned by a small pipe initially contain the same gas at pressue `p_(o)` and abosolute temperature `T_(o^.)` One container is now mantained at the same temperature while the other is heated to `2T_(0^.)` The commmon pressure of the gases will beA. `3/2p_(o)`B. `4/3p_(o)`C. `3/5p_(o)`D. `2p_(o)` |
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Answer» Correct Answer - B `(n_(1)+n_(2))=(n_(1)+n_(2))_(f)` `(p_(o)V)/(RT_(o))+(p_(o)V)/(RT_(o))=(pV)/(RT_(o))+(pV)/(2RT_(o))` `" "p=(4//3)p_(o)` |
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