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Two identical dice are rolled. The probability that same number will appear on each of them will be______________. |
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Answer» total no of events in sample space- 62=36 since both of the dice should have same number thus it can be E= {11,22,33,44,55,66} therefore, total no of required events=6 thus probability of getting the event P(E)=no of elements in E ____________________ no of elements in sample space =6/36=1/6 |
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