1.

Two identical dice are rolled. The probability that same number will appear on each of them will be______________.

Answer»
total no of events in sample space- 62=36
since both of the dice should have same number thus it can be E= {11,22,33,44,55,66}
therefore, total no of required events=6
 
thus probability of getting the event 
      P(E)=no of elements in E
                ____________________
                no of elements in sample space
            
             =6/36=1/6

           


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