Two identical drops of water are falling throgh air with steady speed of V each. If the drops coalesce to form a single drop, what is the new terminal velocity?

Two identical drops of water are falling throgh air with steady speed

1.	Two identical drops of water are falling throgh air with steady speed of V each. If the drops coalesce to form a single drop, what is the new terminal velocity?
Answer» SOLUTION :From conservation of MASS `4/3piR^(3)xxrho=4/3pir^(3)xxrho+4/3pir^(3)xxrho` or `R=2^(1//3)r`, and `V_(T)propr^(2)` (stokes law) `(V^(1))/V=(R^(2))/(r^(2))=2^(2//3)"" :. V^(1)=2^(2//3)V`