Two identical magnets with a length `10cm` and weights `50gf` each are arragned freely with their like poles facing in a vertical glass tube. The upper magnet hangs in air above the lower one so that the distance between the nearest poles of the magnets is `3mm`. Determine the pole strength of the poles of these magnets.

Two identical magnets with a length `10cm` and weights `50gf` each are

1.	Two identical magnets with a length `10cm` and weights `50gf` each are arragned freely with their like poles facing in a vertical glass tube. The upper magnet hangs in air above the lower one so that the distance between the nearest poles of the magnets is `3mm`. Determine the pole strength of the poles of these magnets.
Answer» Correct Answer - `664Am` Let `m_1=m_2=m`, `r=3mm=3xx10^-3m` For hanging in air in balanced position, `F=50g f=50xx10^-3xx98N` As `F=(mu_0)/(4pi)(m_1m_2)/(r^2)` `:. 50xx10^-3xx98=10^-7xx(m.m)/((3xx10^-3)^2)` `m^2=9xx5xx98xx10^-1`, `m=6*64Am`.

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