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Two identical particles of charge `q` each are connected by a masless spring of force cosntant `k` .They are placed over a smoothe horizontal surface .They are released wheen unstretched .If maximum extneison of the spring is `r`,the value of `k` is :(neglect gravitational effect)A. `k=(q)/(r)sqrt((1)/(piepsilon_(0)r))`B. `k=(1)/(4piepsilon_(0))(q^(2))/(l^(2))xx(1)/(r)`C. `k=(2q)/(r)sqrt((1)/(piepsilon_(0)r))`D. `k=(q)/(r)sqrt((2)/(piepsilon_(0)r))` |
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Answer» Correct Answer - 2 `F_(C)=kx` |
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