InterviewSolution
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InterviewSolution
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Two identical photocathodes receive light of frequency `f_(1) andf_(2)` if the velocites of the photo electrons (of mass `m`) coming out are repectively `v_(1) and v_(2)` thenA. `v_(1) - v_(2) = [ ( 2h)/(m) (f_(1) - f_(2))]^(1//2)`B. `v_(1)^(2) - v_(2)^(2) = ( 2h)/(m) (f_(1) - f_(2))`C. `v_(1) + v_(2) = [ ( 2h)/(m) (f_(1) + f_(2))]^(1//2)`D. `v_(1)^(2) + v_(2)^(2) = ( 2h)/(m) (f_(1) + f_(2))` |
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Answer» Correct Answer - B Using Einstein photoelectric equation `E = W_(0) + K_(max)` `hf_(1) = W_(0) + (1)/(2) mv_(1)^(2)` ….(i) `hf_(1) = W_(0) + (1)/(2) mv_(2)^(2)` …..(ii) `rArr h(f_(1) - f_(2)) = (1)/(2) mv(v_(1)^(2) - v_(2)^(2))` `rArr (v_(1)^(2) - v_(2)^(2)) = (2h)/(m) (f_(1) - f_(2))` |
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