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Two identical silicon diodes D and D are connected back to back shown in figure. The reverse saturation current of each diode is 10 amps and the breakdown voltage V is 50 . Evaluate the voltages V and V dropped across the diodes D and D assuming KT/ to be 25 m V. |
| Answer» According to figure, D2 is forward bias, D1 is reverse biased. Reverse saturation current I0 = 10-8A. in clockwise direction. For Diode D2 Is = I0 Here Is = I0 eqv2/kT = 2 or ev2/0.026 = 2 V2 = 0.018 V Drop across D1 = V1 = 5 - 0.018 4.98 V By KVL in mesh, VD1 = -4.98 V, VD2 = 0.018 V. | |