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Two identical simple pendulums oscillate with amplitudes 6 cm and 2 cm respectively. Then ratio of their energies of oscillation areA. `3 : 1`B. `1 : 3`C. `9 : 1`D. `1 : 9` |
Answer» Correct Answer - C `(E_(1))/(E_(2))=(A_(1)^(2))/(A_(2)^(2))=(36)/(4)=(9)/(1)` |
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