1.

Two identical solid copper sphere of radius R are placed in contact with each other. The gravitational force between them is proportional to.

Answer»

Solution :The gravitational force` F = (G(M)(M))/((2R)^(2)) = (G(4/3 PIR^(3)rho))/(4R^(2))`
Mass of the sold sphere`M = 4/3 piR^(3)rho`
` F = (G(16pi^(2)R^(6)rho^(2)))/(9xx 4xx R^(2))`
`F = 4/9 Gpi^(2)rho^(2)R^(4)" , "F prop 4/9 pi^(2) rho^(2) R^(4)`
` :. ` The gravitational force between them is propor tionalto 4TH power of radius .


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