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Two identical sonometer wires have a fundamental frequency of `500 Hz` when kept under the same tension . The percentage change in tension of one of the wires that would cause an occurrence of `5 beats//s` , when both wires vibrate together isA. `0.5 %`B. `1 %`C. `2 %`D. `4 %` |
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Answer» Correct Answer - C `f = (1)/( 2l) sqrt((T)/(m))` `(Delta f)/( f) = (1)/(2) (Delta T)/(T)` `(Delta T)/(T) = 2 (( Delta f))` `( Delta T)/(T) xx 100 = ` percentage change in tension `( Delta T)/( T) = (1)/( 50)` `(Delta T)/( T) = (1)/(50)` `(Delta T)/(T) xx 100 = 2 %` |
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