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Two identical sounds A and B reach a point in the same phase. The resultant sound is C. The loudness of C is n dB higher than the loudness of A. The value of n is (a) 2 (b) 3 (c) 4 (d) 6 |
Answer» Correct Answer is: (d) 6 Let a = amplitude due to A and B, individually. Loudness due to A = IA = ka2 (k = constant) Loudness due to A + B = IC = k(2a)2 = 4IA. n = 10 log10 (IC/IA) = 10 log10 4 = 10 x 0.6 = 6. |
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