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Two immiscible of densities `2.5g//cm^(3)` and `0.8g//cm^(3)` are taken in the ratio of their masses as `2:3` respectively find the average density of the liquid conbination. |
Answer» Let masses be 2m g & 3m, g, then `V=V_(1)+V_(2)=((2m)/(2.5)+(3m)/(0.8))cm^(3)` total mass `=2m+3m+5mg` therefore the average desity `rho=(5m)/(V)=(5m)/((2m)/(2.5)+(3m)/(0.8))=(5)/((2)/(2.5)+(3)/(0.8))=(10)/(9.1)gm//cm^(3)=1.09gm//cm^(3)` |
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