Two inductors `L_(1)` and `L_(2)` are connected in parallel and a time varying current flows as shown. the ratio of current `i-(1)//i_(2)` A. `L_(1)//L_(2)`B. `L_(2)//L_(1)`C. `(L_(1)^(2))/((L_(1)+L_(2)^(2))`D. `(L_(2)^(2))/((L_(1)+L_(2)^(2))`

Two inductors `L_(1)` and `L_(2)` are connected in parallel and a time

1.	Two inductors `L_(1)` and `L_(2)` are connected in parallel and a time varying current flows as shown. the ratio of current `i-(1)//i_(2)` A. `L_(1)//L_(2)`B. `L_(2)//L_(1)`C. `(L_(1)^(2))/((L_(1)+L_(2)^(2))`D. `(L_(2)^(2))/((L_(1)+L_(2)^(2))`
Answer» Correct Answer - B The inductors are in parallel. Therefore, potential difference across them is same, hence, `V_(1)=V_(2)` or `L_(1)((di_(1))/(dt))=L_(2)((di_(2))/(dt))` or `L_(1)(di_(1))=L_(2)(di_(2))` integrating, we get `L_(1)i_(1)=L_(2)i_(2)` or `(i_(1))/(i_(2)=(L_(2))/(L_(1))`

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Two inductors `L_(1)` and `L_(2)` are connected in parallel and a time varying current flows as shown. the ratio of current `i-(1)//i_(2)` A. `L_(1)//L_(2)`B. `L_(2)//L_(1)`C. `(L_(1)^(2))/((L_(1)+L_(2)^(2))`D. `(L_(2)^(2))/((L_(1)+L_(2)^(2))`

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