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Two insulting plates are both uniformly charged in such a way that the potential difference between them is `V_2-V_1=20V`. (i.e., plate 2 is at a higher potential). The plates are separated by `d=0.1m` and can be treated as infinity large. An electron is released from rest on the inner surface of plate 1. What is its speed when it hits plate 2? (`e=1.6xx10^-19C`, `m_e=9.11xx10^-31kg`) A. `7.02 xx 10^(12)m//s`B. `1.87 xx10^(6)m//s`C. `32 xx 10^(-19) m//s`D. `2.65 xx 10^(6)m//s` |
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Answer» Correct Answer - D `(1)/(2) mv^(2)=q Deltav` `V^(2) = (2q Delta V)/(m) =(2xx1.6 xx 10^(-19)xx20)/(9.11 xx 10^(-31))` `V^(2)=7.02 xx 10^(12)` `V=2.65 xx 10^(6)m//s` |
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