1.

Two isolated point poles of strength 30 Am and 60 Am are placed a distance of 0.3 m.The force of repulsion isA. `2xx10^(-3) N`B. `3 xx10^(-2) N`C. `4xx10^(-3)N`D. `3xx10^(-4) N`

Answer» Correct Answer - A
`F=(mu_(0))/(4pi)(m_(1)m_(2))/(r^(2))`
`=(10^(-7)xx30xx60)/(9xx10^(-2))=2xx10^(-3)N`


Discussion

No Comment Found

Related InterviewSolutions