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Two isomers of formula C_4H_9 Br are Aand B, A on reaction with alcoholic KOH gives of molecular formula C_4H_8 by E_1 reaction. B on reaction with alcoholic KOH gives D and E as products by Saytzeff's rule. Identify A, B, C, D, E. |
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Answer» Solution :(i) `C_4H_9Br`: Two isomers may be there : `(A) CH_3 - UNDERSET(Br)underset(|)overset(CH_3) overset(|)C - CH_3` Text butyl bromide and `CH_5 - underset(Br) underset(|)CH - CH-2 -CH_3 ALPHA`-Bromobutane (ii) A on reaction with ALCOHOLIC KOH gives iso BUTYLENE C as the product. (iii) 2-bromobutane B on reactiön with alcoholic KOH follows Saytzeff.s rule to give a MIXTURE of olefins in different amounts.
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