InterviewSolution
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InterviewSolution
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Two large, thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and of magnitude `19xx10^(-22) Cm^(-2)`. What is E (a) to the left of the plates (b) to the right of the plates (c) between the plates ? Here, `sigma = 19xx10^(-22) Cm^(-2)` |
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Answer» (a) On the left, the fields of the two plates are equal and opposite, So E = Zero. (b) On the right, the fields of the two plates are equal and opposite, So the resultant field is `E = (sigma)/(2 in_(0)) + (sigma)/(2 in_(0)) = (sigma)/(in_(0)) = (19xx10^(-22))/(8.85xx10^(-12))` `= 2.14xx10^(-10) NC^(-1)` |
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