Two light vertical springs with equal natural length and spring constants `k_(1)` and `k_(2)` are separated by a distance `l`. Their upper end the ends `A` and `B` of a light horizontal rod `AB`. A vertical downwards force `F` is applied at point `C` on the rod. `AB` will remain horizontal in equilibrium if the distance `AC` is A. `(lk_(1))/(k_(2))`B. `(lk_(1))/(k_(2) + k_(1))`C. `(lk_(2))/(k_(1))`D. `(lk_(2))/(k_(1) + k_(2))`

Two light vertical springs with equal natural length and spring consta

1.	Two light vertical springs with equal natural length and spring constants `k_(1)` and `k_(2)` are separated by a distance `l`. Their upper end the ends `A` and `B` of a light horizontal rod `AB`. A vertical downwards force `F` is applied at point `C` on the rod. `AB` will remain horizontal in equilibrium if the distance `AC` is A. `(lk_(1))/(k_(2))`B. `(lk_(1))/(k_(2) + k_(1))`C. `(lk_(2))/(k_(1))`D. `(lk_(2))/(k_(1) + k_(2))`
Answer» Correct Answer - D `sum ("Moments about" C) =0` `:. (k_(1)x) AC=(k_(2)x) BC` `:. (AC)/(BC) =k_(2)/k_(1)`….(i) `AC + BC =l`….(ii) Soving these two equation we get, `AC=((k_(1))/(k_(1)+k_(2)))l`

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