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Two light waves of amplitudes `A_(1)` and `A_(2)` superimpose with each other such that `A_(1) gt A_(2)`. The difference between maximum and minimum amplitudes isA. `A_(1)`B. `2A_(2)`C. `2A_(1)`D. `A_(2)` |
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Answer» Correct Answer - B `A_("max")-A_("min")= A_(1)+A_(2)-A_(1)+A+A_(2)` `=2A_(2)` |
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