1.

Two light waves of amplitudes `A_(1)` and `A_(2)` superimpose with each other such that `A_(1) gt A_(2)`. The difference between maximum and minimum amplitudes isA. `A_(1)+A_(2)`B. `A_(1)-A_(2)`C. `2A_(1)`D. `2A_(2)`

Answer» Correct Answer - D
`R_("max")=A_(1)+A_(2)`
`R_(min)=A-A_(2)`
Difference at `R_(max) and R_(min)` is,
`R_(max)-R_(min)=A+A_(2)-A_(1)+A_(2)=2A_(2)`


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