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Two lines are drawn through (3,4), each of which makes angle of `45^(@)` with the line `x-y = 2`. Then area of the triangle formed by these lines isA. 9B. `9//2`C. 2D. `2//9` |
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Answer» Correct Answer - B The equation of lines are `y - y_(1) = (m +- tan alpha)/(1 +- m tan alpha) (x-x_(1))` `rArr y - 4 =(1+- tan 45^(@))/(1+-tan 45^(@)) (x-x_(1))` `rArr y - 4 = (1+-1)/(1+-1) (x-3)` `rArr y = 4` or `x = 3` Hence, the lines which make the triangle are `x - y = 2, x = 3` and `y = 4`. THe intersection points of these lines are `(6,4),(3,1)` and (3,4). `:. Delta =(1)/(2) |6(-3)+3(0)+3(3)| =(9)/(2)` |
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