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Two liquid A and B form an ideal solution on mixing. The vapour pressure of solution having 1 mole A and 3 mole B is 550 mm at 300 K temp. The vapour pressure will increased by 10 mm. on addition of 1 mole B to the solution. What will be the vapour pressure of A and B individually ? |
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Answer» <P>500 and 600 `P_(A)^(0)X_(A)+P_(B)^(0)X_(B)=P_("TOT")` `therefore P_(A)^(0)((1)/(1+3))+P_(B)^(0)((3)/(1+3))=550 mm` `therefore 0.25 P_(A)^(0)+0.75P_(B)^(0)=550 mm`….(1) Now add 1 mole B to MIXTURE `0.20 P_(A)^(0)+0.80 P_(B)^(0)=560 mm` .....(2) multiply (1) by 4 `therefore P_(A)^(0)+3P_(B)^(0)=2200` multiply (2) by 5 `therefore P_(A)^(0)+4P_(B)^(0)=2800` `therefore P_(A)^(0)=400 mm =P_(X)^(0)` `P_(A)^(0)=600 mm = P_(Y)^(0)`. |
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