Saved Bookmarks
| 1. |
Two liquids \( A \) and \( B \) are at \( 20^{\circ} C \) and \( 50^{\circ} C \) respectively. When equal masses of them are mixed together, the temperature of the mixture becomes \( 26^{\circ} C \). The ratio of specific heat capacities of \( A \) and \( B \) is \( k: 1 \). Find the value of \( k \). |
|
Answer» When A and B are mixed then final temperature is 26ºC. Heat gained by A = Heat lost by B MASA (26 - 20) = MBSB (50 - 26) \(\because\) MA = MB SA x 6 = SB x 24 \(\frac{S_A}{S_B}=\frac{24}6\) \(\frac{S_A}{S_B}=\frac41\) Given \(\frac{S_A}{S_B}=\frac{K}1\) then \(\frac{K}1=\frac{4}1\) K = 4 |
|